142 viewsDiscrete maths

x1+x2+x3+x4+x5=21 such that

0<=x1<=3, 1<=x2<4 and x3>=15

Anonymous 9 Comments

the ans is 106… whn x4 and x5 are >=0

Answer is 106.

is there nothing mentioned about x4 and x5?

x4 and x5 are greater than or equal to 0

ok i did a calc mistake!! letme correct

Can you please explain why the answer should be equal to the coefficient of y^5?

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