There is no need to solve this question a long way. The simple thing we can observe for a D-FF is that

So, Just look at the column of Q(next) and find where it is 1. The corresponding value of will be the minterm for D.

For :

Just look at the column of and find where it is 1. The corresponding value of will be the minterm for . is 1 for = 011 ; 101 ; 110 ; 111

So, minterms for = (3,5,6,7)

For :

Just look at the column of and find where it is 1. The corresponding value of will be the minterm for . is 1 for = 001 ; 010 ; 101 ; 111

So, minterms for = (1,2,5,7)

For :

Just look at the column of and find where it is 1. The corresponding value of will be the minterm for . is 1 for = 000 ; 010 ; 101 ; 110

So, minterms for = (0,2,5,6)