# Basic maths-calculus-Q8

+1 vote

Value

(A)

(B)

(C)

(D)

reshown May 24

After substituting the values of 0 we are getting 0/0 inderminant form

So we can apply L-hopital rule

$\lim_{x\rightarrow 0}log(1+3x)/e^{2x}-1\\ \\ \lim_{x\rightarrow 0}(3/1+3x)/e^{2x}*2\\ \\ \lim_{x\rightarrow 0}(3/1+0)/1*2=3/2\\ \\ \therefore Answer\ should\ be\ 3/2$

answered May 27 by (112,390 points)