Basic maths-calculus-Q7

+1 vote

The point on the curve which is closest to the point is

(A)

(B)

(C)

(D)

reshown May 24

Distance of (4,0) from any point (x,y) is $\sqrt{(x-4)^2 + (y-0)^2}$

From the above options, only A,B,C points are the part of curve , now find distance from (4,0) to these options A, B, C . hence correct answer is B.

answered May 27 by (112,390 points)
can you please tell formal solution apart from substitution and elimination method
wait I will give you solution. The line from the point(4,0) to the given curve must be a normal to the curve as perpendicular line have the shortest length. So we will use the same concept here. (m1m2 = -1)
+1 vote

This might help with the solution

answered May 28 by (7,650 points)