# Basic maths-calculus-Q2

+1 vote

The value is

(A) 1

(B) -1

(C) 0

(D) does not exist

reshown May 24

Right limit :

$x \rightarrow -2^+$

$x = -2+h; h \rightarrow 0$

$\lim_{h \rightarrow 0} \frac{(h+1)(|h|)}{h}$

Since we are finding right limit, hence, $x \rightarrow -2^+$   ;  $x = -2+h; h \rightarrow 0$; Since,h is positive,so, |h| = h

$\lim_{h \rightarrow 0} \frac{(h+1)(|h|)}{h}$ = 1

Left limit :

$x \rightarrow -2^-$

$x = -2-h; h \rightarrow 0$

$\lim_{h \rightarrow 0} \frac{(-h+1)(|-h|)}{-h}$

Since, h is positive, so, |-h| = h

$\lim_{h \rightarrow 0} \frac{(-h+1)(|-h|)}{-h}$ = -1

So, left limit is Not same as right limit, hence, limit does not exist.

answered May 27 by (112,760 points)