THE GATEBOOK Q&A

CO-Grand Test 1-Q15

A DMA module is transferring characters to memory using cycle stealing, from a device transmitting at 240 Kbps. The processor is fetching instructions at the rate of $10^6$ instructions per second. By how much will the processor be slowed down due to the DMA activity?

(A) 24 %

(B) 18%

(C) 12%

(D) 16%

asked Jun 25 in Computer Organization by gbeditor (10,700 points)
reshown Jun 26 by gbeditor

1 Answer

Best answer

Cycle stealing method: DMA steal for 1 transfer unit (our case character or byte)

240 X 1000 bits $\longrightarrow$ 1 sec

30X1000 bytes (or characters) $\longrightarrow$ 1 sec

DMA asks CPU for 30000 times

CPU slowed down by

$\frac{30000}{10^6}\times 100 \% = 3\%$

But there is no option

If we assume 240 KBps then

240 X 1000 bytes(or characters) $\longrightarrow$ 1 sec

so

Slowed down by

$\frac{240000}{10^6}\times 100 \% = 24\%$

now I am getting the option A

answered Jun 26 by 23rishiyadavpro20 (6,590 points)
edited Jul 24 by 23rishiyadavpro20

But my doubt is "In Kbps b is bytes or there is a mistake in question"

commented Jun 26 by 23rishiyadavpro20 (6,590 points)

So the right value is 30% I guess

commented Jun 28 by 23rishiyadavpro20 (6,590 points)

(30000/10^6)*100= 3% not 30%

commented Jul 24 by tiwaridheeru907pro20 (460 points)

corrected........

commented Jul 24 by 23rishiyadavpro20 (6,590 points)

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