THE GATEBOOK

Normalization Lectures

The product of two numbers is 40 and the sum of their squares is 89. The difference of the number is: (A) 5 (B) 4 (C) 6 (D) 3

(a-b)^2 = (a^2 +b^2) - 2*(a*b)

(a-b)^2 = 89 - 2*40

(a-b)^2 = 89 - 80 = 9

So, (a-b) = 3

Ans.: 3